Sunday, 25 January 2015

Problems on Time and Work asked in various placements

Time & Work:

Work = Men x Days

(M1 D1 T1 E1)/W1 = (M2 D2 T2 E2)/W2

Where M1, M2 = Men
            D1, D2 = Days
            T1, T2 = Time
            E1, E2 = Efficiency


1) 25 men complete a work in 25 days. In how many days one man do the same work?
a) 225
b) 625
c) 125
d) None

Ans: 625

2) A fisherman catch the 5 fishes in 5 days. In how many days 10 man catch 10 fishes?
a) 3
b) 4
c) 5
d) 6

Ans: 5

3) 40 men complete a work in 30 days. All men started work after every 10 days 5 men were left. In how many days the total work completed?
a) 4
b) 5
c) 6
d) 7

Ans: 6

4) 40 men complete a work in 150 days after 10 days 30 members join to them. In how many days the total work should be completed?
a) 20 days
b) 30 days
c) 40 days
d) 80 days

5) A Contract is to be completed in 46 days and 117 members set to work, each work in 8 hours, after 33 days 4/7 of the work is completed. How many additional may be employ. So that the work may be completed in time. Each man working 9 hours a day.
a) 81
b) 91
c) 27
d) 9

Ans: 81

6) 5 men (or) 9 women complete a work in 19 days. In how many days 3 men and 6 women complete the same work?
a) 10 days
b) 15 days
c) 20 days
d) 30 days

Ans: 15 days




0 comments:

Post a Comment