Problems on H.C.F and L.C.M asked in various placements

--> H.C.F = (H.C.F of Numerators)/(L.C.M of Denominators)

--> L.C.M = (L.C.M of Numerators)/(H.C.F of Denominators)

--> Two numbers are said to be co-primes. If their H.C.F is 1.

--> The product of Least powers of common prime factors gives H.C.F.

--> The product of highest powers of all the factors gives L.C.M


1) The LCM of 2⁶ x 3² x 5 x 7, 2³ x 3⁵ x 7 and 2 x 3⁴ x 5 is:
  a) 2⁶ x 3⁵
  b) 2⁶ x 3⁵ x 5
  c) 2⁶ x 3⁵ x 7
  d) 2⁶ x 3⁵ x 5 x 7

2) What is the LCM of 3, 2.7 and .09?
  a) 0.27
  b) 2.7
  c) 27
  d) 2700

3) Find the number to be multiplied by (-6)^(-1). so as to get (-8)^(-1) as the product?
  a) 3/4
  b) -(3/4)
  c) 4/3
  d) -(4/3)

4) What is the value of the expression 3√(√0.000729)?
  a) 0.03
  b) 0.3
  c) 3
  d) 0.27
  e) 0.027

5) What is the value of (3³ * 81² * 2⁰)/(9⁵)?
  a) 0
  b) 3
  c) 1/3
  d) None of the above

6) what is the H.C.F 2³ x 3² x 5 x 7⁴, 2² x 3⁵ x 5² x 7⁶ and 2³ x 5³ x 7²
  a) 980
  b) 840
  c) 740
  d) 540