#include<stdio.h>
#include<conio.h>
void main( )
{
int i=10;
printf("%d,%i",i,i);
}
Options:
A) 10, 20
B) 10, 0
C) 10, 10
D) an error
Answer
Option C)Because we can give % i also for interger datatype
What is the Output of the following Program
#include<stdio.h>
#include<conio.h>
void main( )
{
int i=10;
printf("%d,%i",i,i);
}
Options:
A) 10, 20
B) 10, 0
C) 10, 10
D) an error
Because we can give % i also for interger datatype
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